[백준] 2941 크로아티아 알파벳(python, 구현)

[문제]

[풀이]

croatia_alphabet = ['c=', 'c-', 'd-', 'lj', 'nj', 's=', 'z=']
words = input()
i = 0
result = 0
while i < len(words):
    if i + 2 < len(words) and words[i : i + 3] == 'dz=':
        result += 1
        i += 3
        continue

    elif i + 1 < len(words) and words[i : i + 2] in croatia_alphabet:
        result += 1
        i += 2
        continue

    result += 1
    i += 1
print(result)

• continue를 꼭 써서 중복 카운트 발생안하게~~ 잘하자!

[링크]

https://www.acmicpc.net/problem/2941